Termination w.r.t. Q of the given QTRS could be disproven:

0 QTRS
↳1 NonTerminationProof (⇔)
↳2 NO

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

a(a(x1)) → b(x1)
a(b(c(x1))) → c(c(a(a(a(a(x1))))))

Q is empty.

(1) NonTerminationProof (EQUIVALENT transformation)

We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite.

Found the self-embedding DerivationStructure:
a b c b c c a c c → c c c c a c c b c c a a b c b c c a c c a a a a

a b c b c c a c c → c c c c a c c b c c a a b c b c c a c c a a a a
by OverlapClosure OC 2
a b c b c c a c → c c c c a c c b c c a a b c b c c a a b
by OverlapClosure OC 2
a b c b c c a → c c c c a c c b c c a a b c b a b
by OverlapClosure OC 3
a b c b c c a → c c c c a c c b c c a a a a c b a b
by OverlapClosure OC 3
a b c b c c a → c c c c a c c b a b c c b a b
by OverlapClosure OC 2
a b c b c c → c c c c a c c b a b c c b a a
by OverlapClosure OC 2
a b c b c → c c c c a c c b a b a b
by OverlapClosure OC 3
a b c b c → c c c c a a b c a a b
by OverlapClosure OC 3
a b c b c → c c c c a a a a c a a b
by OverlapClosure OC 3
a b c b c → c c a b c c a a b
by OverlapClosure OC 2
a b c → c c a b a
by OverlapClosure OC 3
a b c → c c a a a a
by original rule (OC 1)
a a → b
by original rule (OC 1)
a b c → c c a a b
by OverlapClosure OC 2
a b c → c c a a a a
by original rule (OC 1)
a a → b
by original rule (OC 1)
a b c → c c a a a a
by original rule (OC 1)
a a → b
by original rule (OC 1)
a b c a → c c b a b
by OverlapClosure OC 3
a b c a → c c a a a b
by OverlapClosure OC 2
a b c → c c a a a a
by original rule (OC 1)
a a → b
by original rule (OC 1)
a a → b
by original rule (OC 1)
a b c → c c b a a
by OverlapClosure OC 3
a b c → c c a a a a
by original rule (OC 1)
a a → b
by original rule (OC 1)
a a → b
by original rule (OC 1)
a b c → c c a a a a
by original rule (OC 1)
a a → b
by original rule (OC 1)
a b c → c c a a b
by OverlapClosure OC 2
a b c → c c a a a a
by original rule (OC 1)
a a → b
by original rule (OC 1)
a b c → c c a a a a
by original rule (OC 1)

(2) NO